Calculul conductei de bransament

^E=E1+E2

^{qc=b(a*c√E+0.004E)}

^a=0.15

^b=1

^c=1

^{qc=0.15√E+0.004E}

^{lcb=15 m}

^ξcb=0.042

^{5 robinete 6}

^{2 coturi 1}

^{3 teuri trecere 0.5}

^{1 ingustare de sectiune 0.5}

^{1 marire de sectiune 0.3}

^{hloc. ap=0.045 bar=0.45 m H2O}

^{hr loc tot=hr loc ap+Σ cb*Wcb/(2*g)*1000=0.45+34.3*1.092*1000/(2*10)= =2038.0415}

^{hr cb=icb*lcb+hloc tot=7.5*15+2038.0415=2.15054 mH2O}

^{Dimensionarea rezervoarelor tampon si a instalatiilor hidraulice anexe:}

^{VURT=150(Gp+10) => tipul rezervorului}

^{Gp>qc =>VURT=150(22+10)=150*32=4800≈5000}

^{qc=19.476 =>Gp=22}

^{Aleg rezervor tip B, model 3, capacitate 5000l.} 

^{hURT=VURT/(l*b)=5000/(2000*1250)= 2 m}

^{htot=hURT+(0.10.0.15)+(0.35.0.5)=0.10+0.40+2=2.55 m}

^{l*b*htot=2000*1250*2550 [mm]}

^{Hdisp=HgRF+HURF+hrcb}

^{HURF=Hdisp-(HgRF+hrcb)}

^{Hdisp=27.6 mH2O}

^{HgRF=1.2+0.3+0.5+0.15+2+0.4/2=4.35}

^{HURF=27.6-6.45=21.15 mH2O}

^{d1=D1/√N=150/√4=75 mm =>d1=80 mm}

^{D2=150*2=300 mm (constructiv)}

^{V1=√(2*g*hu)/(1+ξr)= √2*10*4.35/1=9.2737 m/s}

^{HgRF=Hu=hu=4.35 m}

^ξr=0

^{D3==0.2458m *1000=}

^{=245.832 mm}

^{Ø 278*8 = >D3=278-2*8=262 mm}

^{D3=262 mm}

^{Vas prea plin, de forma tronconica, cu dimensiunile:}

^{Dsup=600 mm}

^{Dinf=300 mm}

^{h= 600 mm}

^D4=d1*

^{ξ0=ξ1=3, ξr=0}

^D4=0.08

^{Ø 219*5 =>D4=209 mm}

^D5=d1*

^ξr=0

^{h2=2 m}

^{D5=0.08*=0.170654 m=170.654 mm}

^{=>Ø 194*5 =>D5=184 mm}

^{D4=D5=209 => Ø 219*5}

^{H*=0.4+0.5+0.10+2=3 m}

^{q=3.14*d12*V1/4=3.14*0.082*9.2736/4=0.046882 m3/s=46.882 l/s}

^{=>D4=250 mm}

ⁱ⁼⁴

^{l5=5 m}

^{l=l4+l5=2+5=7 m}

^{hr=i*l=4*7=28 mmH2O =0.028 mH2O}

^{1 iesire 1*0.5=0.5}

^{1 cot 1*1=1}

^{3 imbinari cu mufe 3*0.25=0.75}

^=>

^{Alegerea pompelor}

^Hp=34

^Gp=72

^Hi=Hp-3=31

^H0=Hp+12

^H0=46

^Gpp=102

^Gp0=46

^{Gpm=(Gpp+Gp0)/2}

^Gpm=74

ⁿ⁼¹⁵

^{VRH=1.1[Gpm*(Hp+10)*(H0+10)]/[4*n*(H0-Hp)*(Hi+10)]}

^VRH=6.749

^{Aleg 2 rezervoare hidrofor cu capacitatea de 4000l (4m3)}

^VRHreal=8

^{nreal=1.1[Gpm*(Hp+10)*(H0+10)]/[4*VRHreal*(H0-Hp)*(Hi+10)]}

^nreal=12.739

^{Avem 13 porniri pe ora.}

^{Vumax=Gpm/(4*nreal)=1.452}

^D=1.2

^h3=0.09

^h4=0.490

^{humax=VRHreal/[2*(p*D2/4)]=3.537}

^{Np=h3+h4+0.08=0.66}

^{N0=Np+humax=4.197}

^NRT=2.6

^{Hg0=N0-NRT=1.597}

^{Hgp=Np-NRT=-1.94}

^ipp=21

^vpp=1.8

^ip0=37

^vp0=2.4

l=10

Sxpp=35

Sxpo=16.5

hrlp=Sxpp*[vpp^2/(2*10)]=5.67

hrlo=Sxpo*[vpo^2/(2*10)]=4.752

hrp=ipp*(1/1000)+hrlp=5.88

hro=ipo*(1/1000)+hrlo=5.122

Hpp=Hp+Hgp+hrp=37.94

Hpo=Ho+Hgo+hrpo=52.719

Pompa aleasa este Lotru 100 F192